document.write( "Question 993190: Find the complement and supplement of (4x -12)° \n" ); document.write( "
Algebra.Com's Answer #612534 by MathLover1(20850)\"\" \"About 
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The complement of an angle is what, when added to it, equals \"90\"°. \r
\n" ); document.write( "\n" ); document.write( "\"alpha%2Bbeta=90\"°\r
\n" ); document.write( "\n" ); document.write( "if \"alpha=%284x+-12%29\"°, then its complement is \"beta=90-%284x+-12%29\"°\r
\n" ); document.write( "\n" ); document.write( "=>\"beta=90-4x+%2B12\"°\r
\n" ); document.write( "\n" ); document.write( "=>\"beta=%28102-4x%29\"°\r
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\n" ); document.write( "\n" ); document.write( "The supplement of an angle is what, when added to it, equals \"180\"°. \r
\n" ); document.write( "\n" ); document.write( "\"alpha%2Bbeta=180\"°\r
\n" ); document.write( "\n" ); document.write( "if \"alpha=%284x+-12%29\"°, then its complement is \"beta=180-%284x+-12%29\"°\r
\n" ); document.write( "\n" ); document.write( "=>\"beta=180-4x+%2B12\"°\r
\n" ); document.write( "\n" ); document.write( "=>\"beta=%28192-4x%29\"°\r
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\n" ); document.write( "\n" ); document.write( "so, if given angle \"%284x+-12%29\"°, its complement is \"%28102-4x%29\"° and its supplement is \"%28192-4x%29\"°\r
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