document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=993095>Question 993095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jae and Jane began at 6:00 a.m. traveling in opposite directions.  If Jae travels at a rate of 9 mph and Jane travels at a rate of 6 mph, what time will it be when Jae and Jane are 12 miles apart? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612474 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612474\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "If Jae travels at a rate of 9 mph <BR>\n" );
document.write( "and Jane travels at a rate of 6 mph<BR>\n" );
document.write( "9x + 6x = 12 miles<BR>\n" );
document.write( "15x = 12<BR>\n" );
document.write( "x = 12/15 = 0.8<BR>\n" );
document.write( "9x = 9 x 0.8 = 7.2<BR>\n" );
document.write( "6x = 6 x 0.8 = 4.8<BR>\n" );
document.write( "Therefore it will be 0.8 x 60 = 48 mins<BR>\n" );
document.write( "when they are 12 miles apart.<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
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