document.write( "Question 993068: The length of a rectangle exceeds its width by 2 feet. If each dimension were increased by 3 feet, the area would be increased by 51 square feet. Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #612467 by stanbon(75887)\"\" \"About 
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The length of a rectangle exceeds its width by 2 feet. If each dimension were increased by 3 feet, the area would be increased by 51 square feet. Find the dimensions.
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\n" ); document.write( "Width:: x
\n" ); document.write( "Length:: x+2
\n" ); document.write( "Original Area:: x^2+2x
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\n" ); document.write( "After change::
\n" ); document.write( "Width:: x+3
\n" ); document.write( "Length:: x+5
\n" ); document.write( "New Area:: (x+3)(x+5) = x^2 + 8x + 15
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\n" ); document.write( "Equation:
\n" ); document.write( "New area - Old area = 51 ft^2
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\n" ); document.write( "x^2+8x+15 - (x^2+2x) = 51
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\n" ); document.write( "6x + 15 = 51
\n" ); document.write( "6x = 36
\n" ); document.write( "x = 6
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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