document.write( "Question 84991: Hi
\n" ); document.write( "I Hope you can help with these Algebra problems.\r
\n" ); document.write( "\n" ); document.write( "5x+3y=9...... y=??\r
\n" ); document.write( "\n" ); document.write( "7x+8y=5.......x=??\r
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Algebra.Com's Answer #61241 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Lets solve this system by elimination/addition\r
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"5%2Ax%2B3%2Ay=9\"
\n" ); document.write( " \"7%2Ax%2B8%2Ay=5\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 5 and 7 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 5 and 7 is 35, we need to multiply both sides of the top equation by 7 and multiply both sides of the bottom equation by -5 like this:
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\n" ); document.write( " \"7%2A%285%2Ax%2B3%2Ay%29=%289%29%2A7\" Multiply the top equation (both sides) by 7
\n" ); document.write( " \"-5%2A%287%2Ax%2B8%2Ay%29=%285%29%2A-5\" Multiply the bottom equation (both sides) by -5
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"35%2Ax%2B21%2Ay=63\"
\n" ); document.write( " \"-35%2Ax-40%2Ay=-25\"
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\n" ); document.write( " Notice how 35 and -35 add to zero (ie \"35%2B-35=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%2835%2Ax-35%2Ax%29%2B%2821%2Ay-40%2Ay%29=63-25\"
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\n" ); document.write( " \"%2835-35%29%2Ax%2B%2821-40%29y=63-25\"
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\n" ); document.write( " \"cross%2835%2B-35%29%2Ax%2B%2821-40%29%2Ay=63-25\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"-19%2Ay=38\"
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\n" ); document.write( " \"y=38%2F-19\" Divide both sides by \"-19\" to solve for y
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\n" ); document.write( " \"y=-2\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"5%2Ax%2B3%2Ay=9\" to solve for x
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\n" ); document.write( " \"5%2Ax%2B3%28-2%29=9\" Plug in \"y=-2\"
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\n" ); document.write( " \"5%2Ax-6=9\" Multiply
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\n" ); document.write( " \"5%2Ax=9%2B6\" Subtract \"-6\" from both sides
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\n" ); document.write( " \"5%2Ax=15\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F5%29%285%29%29%2Ax=%2815%29%281%2F5%29\" Multiply both sides by \"1%2F5\". This will cancel out \"5\" on the left side.
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\n" ); document.write( " \"x=3\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=3\", \"y=-2\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"3\", \"-2\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"5%2Ax%2B3%2Ay=9\"
\n" ); document.write( " \"7%2Ax%2B8%2Ay=5\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"5%2Ax%2B3%2Ay=9\" (red) \"7%2Ax%2B8%2Ay=5\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"3\",\"-2\"). This verifies our answer.
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