document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=992961>Question 992961</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second of two numbers is two less than three times the first. Find these numbers if their sum is 26. I have tried the equations 3x+-2=26 and x-6x=26, but they do not seem to work and I end up with fractions and am not able to find the second number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612372 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The second of two numbers is two less than three times the first. Find these numbers if their sum is 26. I have tried the equations 3x+-2=26 and x-6x=26, but they do not seem to work and I end up with fractions and am not able to find the second number.\r<BR>\n" );
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document.write( "let x=1st of two numbers<BR>\n" );
document.write( "3x-2= second of two numbers <BR>\n" );
document.write( "x+3x-2=26<BR>\n" );
document.write( "4x=24<BR>\n" );
document.write( "x=6<BR>\n" );
document.write( "3x-2=16<BR>\n" );
document.write( "1st of two numbers=24<BR>\n" );
document.write( "2nd of two numbers=16  </SPAN>\n" );
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