document.write( "Question 992862: Carrie has 40 more nickels that Joan has dimes. They both have the same amount of money. How many coins does each girl have? \n" ); document.write( "
Algebra.Com's Answer #612358 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "J=number of Joan's coins; C=number of Carrie's coins=J+40 \n" ); document.write( "$0.10J=$0.05C \n" ); document.write( "$0.10J=$0.05(J+40) \n" ); document.write( "$0.10J=$0.05J+$2.00 \n" ); document.write( "$0.05J=$2.00 \n" ); document.write( "J=40 \n" ); document.write( "ANSWER 1: Joan has 40 dimes. \n" ); document.write( ". \n" ); document.write( "C=J+40=40+40=80 \n" ); document.write( "ANSWER 2: Carrie has 80 nickels. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "$0.10J=$0.05C \n" ); document.write( "$0.10(40)=$0.05(80) \n" ); document.write( "$4.00=$4.00 \n" ); document.write( " |