document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=992875>Question 992875</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in going a certain distance, a train travelling at the rate of 40 km/h takes 2 hours less than a train travelling at 30 km/h. Find the distance. \r<BR>\n" );
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document.write( "Please explain how you logically thought this question through. I am having trouble setting the question up. \r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612339 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612339\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we use rate * time = distance, both trains travel the same distance so we can set their rate * time formulas equal to each other.<BR>\n" );
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document.write( "let t be the time it takes the 30 km/h train to travel the distance, then<BR>\n" );
document.write( "40 * (t-2) = 30 * t<BR>\n" );
document.write( "40t - 80 = 30t<BR>\n" );
document.write( "10t = 80<BR>\n" );
document.write( "t = 8<BR>\n" );
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document.write( "distance traveled by both trains is 8*30 = 240 km\r<BR>\n" );
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