document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=992872>Question 992872</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can I get your help? My problem is this:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x=1%2Bsqrt%284x%5E2%2Bx%2B7%29 ALIGN=MIDDLE  ALT=\"3x=1%2Bsqrt%284x%5E2%2Bx%2B7%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "I started by subtracting the 1 from both sides which gave me <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x-1=sqrt%284x%5E2%2Bx%2B7%29 ALIGN=MIDDLE  ALT=\"3x-1=sqrt%284x%5E2%2Bx%2B7%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > Now, would I add 4x^2 and x which would give me <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt+%285x%5E3%2B7%29 ALIGN=MIDDLE  ALT=\"sqrt+%285x%5E3%2B7%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >Now my equation looks like this: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+3X-1=SQRT%285x%5E3%2B7%29 ALIGN=MIDDLE  ALT=\"+3X-1=SQRT%285x%5E3%2B7%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > From here I would square both sides <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%283x-1%29%5E2=%28sqrt+5x%5E3%2B7%29%5E2 ALIGN=MIDDLE  ALT=\"%283x-1%29%5E2=%28sqrt+5x%5E3%2B7%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "I get 9x^2+3x-1-3x+1-1=5x^3+7. If I continue, 3x-1-3x+1 would cancel out which makes the equation look like this:<BR>\n" );
document.write( "9x^2-1=5x^3+7.  I subtract 9x^2 from both sides and I subtract 7 from both sides so I end up with -8=-4x. Then I divide by -4 and my answer would be 2. Can you verify to see if I made a mistake?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612336 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612336\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x=1+sqrt(4x^2+x+7)<BR>\n" );
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document.write( "3x-1 = sqrt(4x^2+x+7)<BR>\n" );
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document.write( "Square both sides to get:<BR>\n" );
document.write( "9x^2 -6x + 1 = 4x^2 + x + 7<BR>\n" );
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document.write( "5x^2 - 7x - 6 = 0<BR>\n" );
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document.write( "5x^2 - 10x+3x - 6 = 0<BR>\n" );
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document.write( "5x(x-2)+3(x-2) = 0<BR>\n" );
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document.write( "(x-2)(5x+3) = 0<BR>\n" );
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document.write( "x = 2 or x = -3/5<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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