document.write( "Question 992791: Im dying kindly help me please . One number exceeds another by 7 if the larger number is increase by 4 it will be equal to 1 less than 4 times the smaller number decreased by 6 find tbe origibal number.\r
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Algebra.Com's Answer #612305 by ikleyn(52803)\"\" \"About 
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\n" ); document.write( "One number exceeds another by 7. If the larger number is increased by 4 it will be equal to 1 less than 4 times the smaller number decreased by 6. Find the original number.
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\n" ); document.write( "\n" ); document.write( "1.  Your writing was not perfect.  It was difficult to read and to understand it.  I edited and fixed it.\r
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\n" ); document.write( "\n" ); document.write( "2.  Let  x  be the larger number.  Then the other number is (x-7).\r
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document.write( "\" If the larger number is increased by 4\"     ----->   x + 4\r\n" );
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document.write( "\"4 times the smaller number decreased by 6\"   ----->   4*((x-7)-6)\r\n" );
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\n" ); document.write( "\n" ); document.write( "The equation is\r
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\n" ); document.write( "\n" ); document.write( "x + 4 = 4*((x-7)-6) - 1.\r
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\n" ); document.write( "\n" ); document.write( "Simplify and solve it:\r
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\n" ); document.write( "\n" ); document.write( "x + 4 = 4*(x-13) - 1,\r
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\n" ); document.write( "\n" ); document.write( "x + 4 = 4x - 52 - 1,\r
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\n" ); document.write( "\n" ); document.write( "3x = 4 + 52 + 1 = 57,\r
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\n" ); document.write( "\n" ); document.write( "x = \"57%2F3\" = 19.\r
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