document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=992786>Question 992786</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three numbers such that the second number is 3 more than twice the first number,and the third number is four times the first number. The sum of the three numbers is 164 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612286 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612286\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "Make first number = 'x'<BR>\n" );
document.write( "Second number = 3 + 2x<BR>\n" );
document.write( "Third number = 4x<BR>\n" );
document.write( "Total = 164<BR>\n" );
document.write( "So,<BR>\n" );
document.write( "x + (3 + 2x) + 4x = 164<BR>\n" );
document.write( "x + 3 + 2x + 4x = 164<BR>\n" );
document.write( "Collect like terms:<BR>\n" );
document.write( "x + 2x + 4x = 164 - 3<BR>\n" );
document.write( "7x = 161<BR>\n" );
document.write( "x = 23<BR>\n" );
document.write( "First number = 23<BR>\n" );
document.write( "Second number = 49<BR>\n" );
document.write( "Third number = 92<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );