document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=992765>Question 992765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6 kilo of sugar if 2.5 lb. cost P70<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612268 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612268\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "6 kilograms = 13.2277 pounds<BR>\n" );
document.write( "If 2.5 pounds cost P70<BR>\n" );
document.write( "1 pound = P70/2.5<BR>\n" );
document.write( "1 pound = P28<BR>\n" );
document.write( "13.2277 pounds = 13.2277 x P28<BR>\n" );
document.write( "13.2277 pounds = P370.3756 (4 decimal places)<BR>\n" );
document.write( "Hope this helps :-)<BR>\n" );
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