document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=992744>Question 992744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sides of a rectangular swimming pool are 50m & 30m. What is the distance in meters of the opposite corners? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612265 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612265\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "Consider the pool as a right angled triangle.<BR>\n" );
document.write( "So, 30^2 + 50^2 = (distance of opposite corners)^2<BR>\n" );
document.write( "=> 900 + 2,500 = (distance of opposite corners)^2<BR>\n" );
document.write( "=> 3,400 = (distance of opposite corners)^2<BR>\n" );
document.write( "=> (distance of opposite corners) = sqrt 3400<BR>\n" );
document.write( "=> distance of opposite corners = 58.31 meters (2 decimal places)<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
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