document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=68041>Question 68041</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three consecutive odd integers is 201. Find the integers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #61226 by </B><A HREF=/tutors/aboutme.mpl?userid=JohnsenP><B>JohnsenP(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JohnsenP><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=61226\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the one integer be        x,<BR>\n" );
document.write( "The second integer be         x+2,<BR>\n" );
document.write( "The third integer is then     x+4,<BR>\n" );
document.write( "If their sum is 201, the equation is\r<BR>\n" );
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document.write( "     x + ( x + 2 ) + ( x + 4 ) = 201<BR>\n" );
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document.write( "                    3x + 6 - 6 = 201 - 6<BR>\n" );
document.write( "                            <BR>\n" );
document.write( "                            3x = 195\r<BR>\n" );
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document.write( "                          3x/3 = 195/3<BR>\n" );
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document.write( "                             x = 65 first odd integer\r<BR>\n" );
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document.write( " Plug 65 to the second integer yields, 65 + 2 = 67<BR>\n" );
document.write( " Plug 65 to the third integer yields,  65 + 3 = 69\r<BR>\n" );
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document.write( " Proof;\r<BR>\n" );
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document.write( "  65 + 67 + 69 = 201\r<BR>\n" );
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document.write( "                             </SPAN>\n" );
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