document.write( "Question 992754: Given that sinx=3/5 and it is in quadrant 1. Find sin2x+cos2x \n" ); document.write( "
Algebra.Com's Answer #612245 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "If sin x = 3/5
\n" ); document.write( "cos x = 4/5
\n" ); document.write( "tan x = 3/4
\n" ); document.write( "..........
\n" ); document.write( "sin 2x = 2 sin x cos x
\n" ); document.write( "sin 2x = 2 (3/5)(4/5)
\n" ); document.write( "sin 2x = 24/25
\n" ); document.write( "..........
\n" ); document.write( "cos 2x = 2 cos^2 x - 1
\n" ); document.write( "cos 2x = 2(4/5)^2 - 1
\n" ); document.write( "cos 2x = 2(16/25) - 1
\n" ); document.write( "cos 2x = 32/25 - 1
\n" ); document.write( "cos 2x = 32/25 - 25/25
\n" ); document.write( "cos 2x = 7/25
\n" ); document.write( "..........
\n" ); document.write( "Hope this helps :-)
\n" ); document.write( "
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