document.write( "Question 992754: Given that sinx=3/5 and it is in quadrant 1. Find sin2x+cos2x \n" ); document.write( "
Algebra.Com's Answer #612245 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "If sin x = 3/5 \n" ); document.write( "cos x = 4/5 \n" ); document.write( "tan x = 3/4 \n" ); document.write( ".......... \n" ); document.write( "sin 2x = 2 sin x cos x \n" ); document.write( "sin 2x = 2 (3/5)(4/5) \n" ); document.write( "sin 2x = 24/25 \n" ); document.write( ".......... \n" ); document.write( "cos 2x = 2 cos^2 x - 1 \n" ); document.write( "cos 2x = 2(4/5)^2 - 1 \n" ); document.write( "cos 2x = 2(16/25) - 1 \n" ); document.write( "cos 2x = 32/25 - 1 \n" ); document.write( "cos 2x = 32/25 - 25/25 \n" ); document.write( "cos 2x = 7/25 \n" ); document.write( ".......... \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |