document.write( "Question 992760: Frank had a bagful of coins totaling $13.00. He said, \"Guess how many of each coin type I have if six less quarters than dimes and ten more than seven times as many nickles than dimes?\" (Solve with only using one variable)\r
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Algebra.Com's Answer #612243 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Let D = the number of dimes. Then\r\n" );
document.write( "The value of the dimes = 0.10D\r\n" );
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\n" ); document.write( "I have...six less quarters than dimes
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document.write( "The number of the quarters = D-6\r\n" );
document.write( "Value of quarters = 0.25(D-6)\r\n" );
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\n" ); document.write( "and ten more than seven times as many nickles than dimes
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document.write( "number of nickels = 7D+10\r\n" );
document.write( "Value of nickels = 0.05(7D+10)\r\n" );
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document.write( "coins totaling $13.00\r\n" );
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document.write( "Value of dimes + Value of quarters + value of nickels = 13.00\r\n" );
document.write( "       D       +      0.25(D-6)    +    0.05(7D+10)   = 13.00\r\n" );
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document.write( "Multiply through by 100 to clear decimals:\r\n" );
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document.write( "  100D + 25(D-6) + 5(7D+10) = 1300\r\n" );
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document.write( "100D + 25D - 150 + 37D + 50 = 1300 \r\n" );
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document.write( "That works out to 8 3/4 dimes, so something is wrong \r\n" );
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document.write( "Edwin
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