document.write( "Question 992752: 5x^(1/3) + 3x^(2/3) = 8\r
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document.write( "Can you help me? I hope I wrote it right; it's 5x to the one third plus 3x to the two thirds. Thank you! \n" );
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Algebra.Com's Answer #612241 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 5x^(1/3) + 3x^(2/3) = 8 \n" ); document.write( "----- \n" ); document.write( "Rewrite as:: \n" ); document.write( "3(x^(1/3))^2 + 5(x^(1/3)) - 8 = 0 \n" ); document.write( "------- \n" ); document.write( "Note:: This is a quadratic equation. The variable is x^(1/3) \n" ); document.write( "---- \n" ); document.write( "Let x^(1/3) = w \n" ); document.write( "--- \n" ); document.write( "Rewrite the equation as:: \n" ); document.write( "3w^2 + 5w - 8 = 0 \n" ); document.write( "Factor:: \n" ); document.write( "3w^2 + 8w-3w - 8 = 0 \n" ); document.write( "w(3w+8) - (3w+8) = 0 \n" ); document.write( "(3w+8)(w-1) = 0 \n" ); document.write( "---- \n" ); document.write( "w = -8/3 or w = 1 \n" ); document.write( "---- \n" ); document.write( "Now, solve for \"x\" \n" ); document.write( "x^(1/3) = (-8/3) or x^(1/3) = 1 \n" ); document.write( "---- \n" ); document.write( "x = (-8/3)^3 or x = 1^3 \n" ); document.write( "--- \n" ); document.write( "x = -512/27 or x = 1 \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |