document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=991736>Question 991736</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find all solutions of csc x = -2, where 0 &#8804; x &#8804; 2&#960;. Can you explain step by step how you got the answer. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612210 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612210\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Find all solutions of csc x = -2, where 0 &#8804; x &#8804; 2&#960;. <BR>\n" );
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document.write( "If csc(x) = -2, sin(x) = 1/csc(x) = -1/2<BR>\n" );
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document.write( "If sin = -1/2, the reference angle is pi/6<BR>\n" );
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document.write( "Since sin is negative in QIII and QIV<BR>\n" );
document.write( "x = pi+(pi/6) = (7/6)pi<BR>\n" );
document.write( "or x = (2pi)-(pi/6) = (11/6)pi<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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