document.write( "Question 992567: Jen Butler has been pricing speed-pass train fares for a group trip to New York. Three adults and four children must pay $121. Two adults and three children must pay $86. Find the price for the adult tickets and child's tickets. \n" ); document.write( "
Algebra.Com's Answer #612164 by vleith(2983)\"\" \"About 
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Let adult tickets cost A and child tickets cost C. You are told
\n" ); document.write( "\"3A+%2B+4C+=+121\"
\n" ); document.write( "\"2A+%2B+3C+=+86\"\r
\n" ); document.write( "\n" ); document.write( "Multiply the first equation by 2 and the second by 3 to get
\n" ); document.write( "\"6A+%2B+8C+=+242\"
\n" ); document.write( "\"6A+%2B+9C+=+258\"
\n" ); document.write( "Now subtract the fourth equation from the third to get
\n" ); document.write( "\"-C+=+-16\"
\n" ); document.write( "Children cost 16 each\r
\n" ); document.write( "\n" ); document.write( "Use that to solve for A.
\n" ); document.write( "\"3A+%2B+4%2A16+=+121\"
\n" ); document.write( "\"3A+=+57\"
\n" ); document.write( "\"A=19\"
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