document.write( "Question 992548: Two trains leave towns 614km apart at the same time and travel
\n" ); document.write( "toward each other. One train travels 11/kmh faster than the
\n" ); document.write( "other. If they meet in 2 hours, what is the rate of each train?
\n" ); document.write( "

Algebra.Com's Answer #612149 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
Two trains leave towns 614km apart at the same time and travel
\n" ); document.write( "toward each other. One train travels 11/kmh faster than the
\n" ); document.write( "other. If they meet in 2 hours, what is the rate of each train?
\n" ); document.write( "
\r\n" );
document.write( "Let the slower train's speed be x km/h\r\n" );
document.write( "Then the faster train's speed is x+11 km/h\r\n" );
document.write( "\r\n" );
document.write( "Therefore their speed of approach is the sum of their speeds\r\n" );
document.write( "or (x)+(x+11) or (2x+11) km/h.\r\n" );
document.write( "\r\n" );
document.write( "Since \"matrix%281%2C2%2CAPPROACH%2CRATE%29\"\"%22%22=%22%22\"\"DISTANCE%2FTIME\"\"%22%22=%22%22\"\"matrix%281%2C2%2C614%2Ckm%29%2Fmatrix%281%2C2%2C2%2Chours%29\"\"%22%22=%22%22\"\"matrix%281%2C2%2C307%2Ckm%2Fh%29\"\r\n" );
document.write( "\r\n" );
document.write( "So \"2x%2B11\"\"%22%22=%22%22\"\"307\"\r\n" );
document.write( "    \"2x\"\"%22%22=%22%22\"\"296\"\r\n" );
document.write( "        \"x\"\"%22%22=%22%22\"\"148\"\r\n" );
document.write( "\r\n" );
document.write( "The slower train is traveling 148 km/h\r\n" );
document.write( "The faster train is traveling 148+11 = 159 km/h\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );