document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=84939>Question 84939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Greetings, My question is:\r<BR>\n" );
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document.write( "The amount A in an account after t years from an initial principle P invested at an annual rate r compounded continuously is given by A = Pert where r is expressed as a decimal.  How many years will it take an initial investment of $1,000 to grow to $1,700 at the rate of 4.42% compounded continuously?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #61214 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=61214\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The amount A in an account after t years from an initial principle P invested at an annual rate r compounded continuously is given by A = Pert where r is expressed as a decimal.  How many years will it take an initial investment of $1,000 to grow to $1,700 at the rate of 4.42% compounded continuously?<BR>\n" );
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document.write( "A=Pe^(rt)<BR>\n" );
document.write( "1700 = 1000e^(0.0442t)<BR>\n" );
document.write( "1.7 = e^(0.0442t)<BR>\n" );
document.write( "Take the natural log of both sides to get:<BR>\n" );
document.write( "0.0442t= ln1.7<BR>\n" );
document.write( "t = [ln1.7]/0.0442 <BR>\n" );
document.write( "t =  12.005 years<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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