document.write( "Question 992526: One person had a habit of spending money according to dates.one night He calculated total spending of five consecutive days. Monday to Friday and he found that he spent rupees 63 in five days. Identify dates \n" ); document.write( "
Algebra.Com's Answer #612122 by ikleyn(52847)\"\" \"About 
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\n" ); document.write( "Answer.  There is only one solution:\r
\n" ); document.write( "\n" ); document.write( "              28  and  29  of February of a leap-year and  1, 2,  and  3  of March.\r
\n" ); document.write( "\n" ); document.write( "              (28 + 29 + 1 + 2 + 3 = 63). \r
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\n" ); document.write( "\n" ); document.write( "If these days would be inside one month,  then the dates are  (x-2),  (x-1),  x,  (x+1)  and  (x+2),  where x is the date in the middle of  5 days. \r
\n" ); document.write( "\n" ); document.write( "Then the sum must be multiple of  5,  since \r
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\n" ); document.write( "\n" ); document.write( "(x-2) + (x-1) + x + (x+1) + (x+2) = 5x.\r
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\n" ); document.write( "\n" ); document.write( "But the integer  63  is not multiple of  5.  Contradiction. \r
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\n" ); document.write( "\n" ); document.write( "Hence,  the dates are partly the end of some month and the beginning of the next month. \r
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\n" ); document.write( "\n" ); document.write( "Then,  it is easy to check that the dates  28,  29,  1,  2  and 3  satisfy the condition  28 + 29 + 1 + 2 + 3 = 63. \r
\n" ); document.write( "\n" ); document.write( "Next,  it is easy to check that there is no other solution.\r
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\n" ); document.write( "\n" ); document.write( "This problem was just offered and solved in this forum one-two weeks ago (# 990684, the link \r
\n" ); document.write( "\n" ); document.write( "http://www.algebra.com/algebra/homework/word/misc/Miscellaneous_Word_Problems.faq.question.990684.html ).\r
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\n" ); document.write( "\n" ); document.write( "The problem and the solution were also placed in the lesson  Spending money according to dates  in this site.\r
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