document.write( "Question 992532: an electronic store sells about 70 of a new model of digital cameras per month at a proce of 320$ each. for each 20$ decrease in price, about 5 more cameras per month are sold. write a function that models the revenue. How many times should they lower the price by 20$ to maximize revenue. What price should they sell the camera to maximize revenue. How many cameras will they sell when they maximize revenue. What is the maximum revenue. \n" ); document.write( "

Algebra.Com's Answer #612119 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
an electronic store sells about 70 of a new model of digital cameras per month at a proce of 320$ each. for each 20$ decrease in price, about 5 more cameras per month are sold. write a function that models the revenue. How many times should they lower the price by 20$ to maximize revenue. What price should they sell the camera to maximize revenue. How many cameras will they sell when they maximize revenue. What is the maximum revenue.
\n" ); document.write( "----
\n" ); document.write( "Revenue = (# of units sold)(price per unit)
\n" ); document.write( "-----
\n" ); document.write( "R(x) = (70+5x)(320-20x) = -100x^2 + 200x + 320*70
\n" ); document.write( "----
\n" ); document.write( "R'(x) = -200x + 200
\n" ); document.write( "-----
\n" ); document.write( "Solve for \"x\"::
\n" ); document.write( "-200x + 200 = 0
\n" ); document.write( "x = 1
\n" ); document.write( "----
\n" ); document.write( "Ans: To maximize Revenue
\n" ); document.write( "Sell at 320-20 = $300 per unit
\n" ); document.write( "# of units sold will be 70+5 = 75
\n" ); document.write( "----------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

\n" );