document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=992525>Question 992525</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A newspaper carrier has $3.90 in change. He has three more quarters than dimes but five times as many nickels as quarters. How many coins of each type doe he have?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612112 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612112\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A newspaper carrier has $3.90 in change. He has three more quarters than dimes but five times as many nickels as quarters. How many coins of each type does he have? <BR>\n" );
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document.write( "5n + 10d + 25q = 390 cents<BR>\n" );
document.write( "q = d + 3<BR>\n" );
document.write( "n = 5q<BR>\n" );
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document.write( "Substitue for d and n and solve for \"q\"::<BR>\n" );
document.write( "5(5q) + 10(q-3) + 25q = 390<BR>\n" );
document.write( "25q + 10q - 30 + 25q = 390<BR>\n" );
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document.write( "60q = 420<BR>\n" );
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document.write( "q = 7 (# of quarters)<BR>\n" );
document.write( "d = q-3 = 4 (# of dimes)<BR>\n" );
document.write( "n = 5q = 35 (# of nickels)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "------------<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );