document.write( "Question 992431: write an equation and solve\r
\n" ); document.write( "\n" ); document.write( "An investor has $7500 invested at one rate and $6200 invested at a different rate. If the second investment is at a rate 2% lower than the first, find the rate for each investment if his combined annual interest income is $698.
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Algebra.Com's Answer #612091 by Theo(13342)\"\" \"About 
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rate is equal to percent / 100.
\n" ); document.write( "2% is therefore equal to a rate of .02.\r
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\n" ); document.write( "\n" ); document.write( "x is the rate that 7500 is invested at.
\n" ); document.write( "x - .02 is the rate that 6200 is invested at.\r
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\n" ); document.write( "\n" ); document.write( "your equation is:\r
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\n" ); document.write( "\n" ); document.write( "7500 * x + 6200 * (x-.02) = 698\r
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\n" ); document.write( "\n" ); document.write( "simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "7500 * x + 6200 * x - .02 * 6200 = 698\r
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\n" ); document.write( "\n" ); document.write( "simplify further to get:\r
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\n" ); document.write( "\n" ); document.write( "(7500 + 6200) * x - 124 = 698\r
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\n" ); document.write( "\n" ); document.write( "subtract 124 from both sides of the equation and simplify further to get:\r
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\n" ); document.write( "\n" ); document.write( "13700 * x = 822.\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of the equation by 13700 to get:\r
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\n" ); document.write( "\n" ); document.write( "x = 822 / 13700 = .06\r
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\n" ); document.write( "\n" ); document.write( "x - .02 = .06 - .02 = .04\r
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\n" ); document.write( "\n" ); document.write( "7500 was invested at 6% and 6200 was invested at 4%.\r
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\n" ); document.write( "\n" ); document.write( "7500 * .06 + 6200 * .04 = 450 + 248 = 698.\r
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\n" ); document.write( "\n" ); document.write( "your solution is that the rate for 7500 is 6% and the rate for 6200 is 4%.\r
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