document.write( "Question 992301: Ana run 15 kilometer in going to the park at a constant rate, it takes her 30 minutes to reach the park in time for her lesson/by direct variation \n" ); document.write( "
Algebra.Com's Answer #612082 by farohw(175) You can put this solution on YOUR website! \r \n" ); document.write( "\n" ); document.write( "At a constant rate, distance (d) is 15 km and time (t) is 30 minutes where d and t are in direct variation of each other. In other words, the distance Ana runs varies directly with the amount of time she has been running. The formula will be d = kt, k is the constant.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Assuming you want to determine the distance travelled per minute, the constant ratio is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "k = distance travelled/time = 15 km/30 minutes = 0.5 km/minute. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, Ana travels 1/2 kilometer for every minute she runs.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Another way you can set up the problem through direct variation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "When d = 15, t = 30\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "d = kt --> 15 = 30k\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "15/30 = 30k/30 --> k = 1/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Verify:\r \n" ); document.write( "\n" ); document.write( "d = kt --> d = (1/2)t\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "15 = (1/2)*30 --> 15 = 15 is true.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |