document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=992419>Question 992419</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangular garden is 5 feet greater than the width. The area of the garden is 300 square feet. Find the length and the width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612073 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612073\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So, the length= W+5. Therefore, using this value for the length and applying it to the formula for area of the rectangle:\r<BR>\n" );
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document.write( "W*W+5= 300<BR>\n" );
document.write( "W^2+5W= 300 Now we subtract 300 from both sides:<BR>\n" );
document.write( "W^2+5W-300= 0 Factor the left side:<BR>\n" );
document.write( "(W-15)(W+20)= 0 Break into 2 equations<BR>\n" );
document.write( "W-15= 0 or W+20=0 Solve each<BR>\n" );
document.write( "W= 15 or W= -20 Let's try our first answer, 15:<BR>\n" );
document.write( "15*15+5= 300<BR>\n" );
document.write( "15*20= 300 and 15*20= 300 so this answer is correct The W=15 and L=20<BR>\n" );
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