document.write( "Question 992369: Mary has $6.00 in nickels, dimes, and quarters. If she has twice as many dimes as quarters and ninety-eight more nickels than dimes, how many coins of each type does she have? \n" ); document.write( "
Algebra.Com's Answer #612010 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Let represent the number of quarters. Then is the number of dimes and is the number of nickels. Nickels are worth 5 cents, dimes are worth 10 cents, and quarters are worth 25 cents. The total value of the coins is $6.00 which is equivalent to 600 cents. Hence:\r
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\n" ); document.write( "\n" ); document.write( "Solve for , then calculate , and \r
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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