document.write( "Question 992314: sofia is 3 years older than Eunice.In 5 years, Sofia will be twice as old as Eunice will then be. Find their present ages
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Algebra.Com's Answer #611999 by Timnewman(323)![]() ![]() You can put this solution on YOUR website! let Eunice age be\"x\" \n" ); document.write( "Sofia's age=x+3 \n" ); document.write( "In 5yrs time, \n" ); document.write( "Eunice;s age=x+5, \n" ); document.write( "Sofia's age=x+8 \n" ); document.write( "But sofia will be twice as old, \n" ); document.write( "Then, \n" ); document.write( "x+8=2(x+5) \n" ); document.write( "x+8=2x+10 \n" ); document.write( "2x-x=8-10 \n" ); document.write( "x=-2 \n" ); document.write( "But age cannot be nagative, \n" ); document.write( "Therefore Eunice age is 2yrs, \n" ); document.write( "Sofia's age 5yrs.\r \n" ); document.write( "\n" ); document.write( " FOR MORE UNDERSTANDING, \n" ); document.write( "CLICK HERE: \n" ); document.write( "http//www.algebra.com/cgi-bin/jump-to-question.mpl?question=991063 \n" ); document.write( "OR SEE \n" ); document.write( "http//www.algebra.com/cgi-bin/jump-to-question.mpl?question=990905 \n" ); document.write( "HOPE THIS HELPS? \n" ); document.write( " |