document.write( "Question 992314: sofia is 3 years older than Eunice.In 5 years, Sofia will be twice as old as Eunice will then be. Find their present ages
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Algebra.Com's Answer #611999 by Timnewman(323)\"\" \"About 
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let Eunice age be\"x\"
\n" ); document.write( "Sofia's age=x+3
\n" ); document.write( "In 5yrs time,
\n" ); document.write( "Eunice;s age=x+5,
\n" ); document.write( "Sofia's age=x+8
\n" ); document.write( "But sofia will be twice as old,
\n" ); document.write( "Then,
\n" ); document.write( "x+8=2(x+5)
\n" ); document.write( "x+8=2x+10
\n" ); document.write( "2x-x=8-10
\n" ); document.write( "x=-2
\n" ); document.write( "But age cannot be nagative,
\n" ); document.write( "Therefore Eunice age is 2yrs,
\n" ); document.write( "Sofia's age 5yrs.\r
\n" ); document.write( "\n" ); document.write( " FOR MORE UNDERSTANDING,
\n" ); document.write( "CLICK HERE:
\n" ); document.write( "http//www.algebra.com/cgi-bin/jump-to-question.mpl?question=991063
\n" ); document.write( "OR SEE
\n" ); document.write( "http//www.algebra.com/cgi-bin/jump-to-question.mpl?question=990905
\n" ); document.write( "HOPE THIS HELPS?
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