document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=992352>Question 992352</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Algebra 2 word problem:<BR>\n" );
document.write( "The width of the rectangle is 3 feet less than its length. The perimeter of the rectangle is 110 feet. Find its dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #611965 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=611965\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The width of the rectangle is 3 feet less than its length. The perimeter of the rectangle is 110 feet. Find its dimensions. <BR>\n" );
document.write( "---<BR>\n" );
document.write( "length:: x<BR>\n" );
document.write( "width::: x-3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "P = 2(length + width)<BR>\n" );
document.write( "110 = 2(x + x-3)<BR>\n" );
document.write( "55 = 2x-3<BR>\n" );
document.write( "2x = 58<BR>\n" );
document.write( "x = 29 (width)<BR>\n" );
document.write( "x-3 = 26 (length)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );