document.write( "Question 992241: A person standing close to the edge on the top of a 270-foot building throws a baseball vertically upward. The quadratic equation\r
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document.write( "\qquad\qquad h = -16 t^2 + 160 t + 270\r
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document.write( "models the ball's height \, h \, above the ground in feet, t seconds after it was thrown.\r
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document.write( "How high is the ball after 5 seconds?\r
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document.write( " ??feet.\r
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document.write( "How many seconds does it take until the ball finally hits the ground? Round to the nearest tenth of a second.\r
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document.write( "?? seconds.
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document.write( "(I plugged in 5, then set it equal to 0, none of it worked, I'm probably doing it wrong) \n" );
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Algebra.Com's Answer #611959 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! h = -16 t^2 + 160 t + 270 \n" ); document.write( "to find the height of the ball after 5 seconds substitute 5 for t \n" ); document.write( "h = -16(5^2) + (160*5) + 270 \n" ); document.write( "h = 670 feet high after 5 seconds \n" ); document.write( "***************************************************************** \n" ); document.write( "to find when the ball hits the ground, set h = 0 and solve the quadratic for t \n" ); document.write( "-16 t^2 + 160 t + 270 = 0 \n" ); document.write( "multiply both sides of = by -1 \n" ); document.write( "16t^2 - 160t - 270 = 0 \n" ); document.write( "use quadratic formula to solve for t \n" ); document.write( "t = (160 + sqrt(160^2 - (4*16*(-270)))) / (2*16) = 11.471089553 approx 11.5 \n" ); document.write( "t = (160 - sqrt(160^2 - (4*16*(-270)))) / (2*16) = −1.471089553 approx -1.5 \n" ); document.write( "**************************************************************************** \n" ); document.write( "we want the positive value for t \n" ); document.write( "t = 11.5 seconds for the ball to hit the ground \n" ); document.write( " \n" ); document.write( " |