document.write( "Question 990056: In four years time, father will be three times as old as his son. Six years ago, he was 7 times as old as his son. What is their present ages?
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Algebra.Com's Answer #611894 by satyareddy22(84)\"\" \"About 
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Let the age of father be x and son be y.
\n" ); document.write( "x+4=3(y+4)=3y+12
\n" ); document.write( "x+4=3y+12
\n" ); document.write( "x-3y=8----(1)
\n" ); document.write( "x-6=7(y-6)=7y-42
\n" ); document.write( "x-6=7y-42
\n" ); document.write( "x-7y=-36----(2)
\n" ); document.write( "Solving (1) & (2)
\n" ); document.write( "From (1) x=8+3y,substitute in (2)
\n" ); document.write( "8+3y-7y=-36
\n" ); document.write( "-4y=-44
\n" ); document.write( "y=44/4=11
\n" ); document.write( "y=11
\n" ); document.write( "x=8+3*11=8+33=41=>x=41 yrs
\n" ); document.write( "So the father age is 41 years and son age is 11 years.\r
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