document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=991876>Question 991876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father and son's age is 50. After five years, the father is three times the age of the son. How old is their present age? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #611881 by </B><A HREF=/tutors/aboutme.mpl?userid=satyareddy22><B>satyareddy22(84)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=satyareddy22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=611881\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the age of father be x and the age of son be y.<BR>\n" );
document.write( "x+y=50-----------(1)<BR>\n" );
document.write( "x+5=3(y+5)=3y+15<BR>\n" );
document.write( "x+5=3y+15=>x-3y=10-----(2)<BR>\n" );
document.write( "solving (1)& (2)<BR>\n" );
document.write( "from (1) x=50-y,substituting in(2)<BR>\n" );
document.write( "50-y-3y=10<BR>\n" );
document.write( "3y+y=50-10<BR>\n" );
document.write( "4y=40=>y=40/4=10<BR>\n" );
document.write( "y=10yrs<BR>\n" );
document.write( "x=50-10=40=>x=40yrs<BR>\n" );
document.write( "Therefore the age of father is 40years & age of son is 10 years. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );