document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=991879>Question 991879</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Romulo is twice as old as his nephew. the sum of their ages is 108. find their ages<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #611879 by </B><A HREF=/tutors/aboutme.mpl?userid=satyareddy22><B>satyareddy22(84)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=satyareddy22><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=611879\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the age of Romulo be x and the age of his nephew be y.<BR>\n" );
document.write( "Romulo is twice as old as his nephew<BR>\n" );
document.write( "=>x=2y<BR>\n" );
document.write( "sum of their ages is 108<BR>\n" );
document.write( "=>x+y=1080----(1)<BR>\n" );
document.write( "Now substituting x=2y in (1)<BR>\n" );
document.write( "2y+y=108=>3y=108=>y=108/3=36=>y=36yrs<BR>\n" );
document.write( "x=2(36)=72=>x=72yrs<BR>\n" );
document.write( "Therefore the age of Romulo=72years and age of his nephew =36years\r<BR>\n" );
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