document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=992123>Question 992123</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the dimensions of a rectangle with a perimeter of 64 meters if its length is 4 meters less than twice the width. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #611868 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=611868\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  .<BR>\n" );
document.write( "W=width; L=length=2W-4m<BR>\n" );
document.write( ".<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "64m=2(2W-4m+W)<BR>\n" );
document.write( "32m=3W-4m<BR>\n" );
document.write( "36m=3W<BR>\n" );
document.write( "12m=W . ANSWER 1: The width is 12 meters.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "L=2W-4m=2(12m)-4m=24m-4m=20m<BR>\n" );
document.write( "ANSWER 2: The length is 20 meters.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "P=2(L+W)<BR>\n" );
document.write( "64m=2(20m+12m)<BR>\n" );
document.write( "64m=2(32m)<BR>\n" );
document.write( "64m=64m </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );