document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=992198>Question 992198</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Twice a number minus a second number is -1. Twice the second number added to three times the first number is 9. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #611829 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=611829\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Twice a number minus a second number is -1. Twice the second number added to three times the first number is 9. Find the number.\r<BR>\n" );
document.write( "\n" );
document.write( "let x=number<BR>\n" );
document.write( "let y=2nd number<BR>\n" );
document.write( "2x-y=-1<BR>\n" );
document.write( "y=-2x+1<BR>\n" );
document.write( "plug in y for x\r<BR>\n" );
document.write( "\n" );
document.write( "2(-2x+1)+3x=9<BR>\n" );
document.write( "-4x+2+3x=9<BR>\n" );
document.write( "x=7<BR>\n" );
document.write( " number=7<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );