document.write( "Question 992166: Please help me out with this math.
\n" ); document.write( "The numerator of a fraction is 5 less than its denominator. If 6 is added to the numerator and 4 to the denominator,the fraction is double. What is the fraction?
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Algebra.Com's Answer #611779 by ikleyn(52790)\"\" \"About 
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\n" ); document.write( "The numerator of a fraction is 5 less than its denominator. If 6 is added to the numerator and 4 to the denominator, the fraction is double. What is the fraction?
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\n" ); document.write( "\n" ); document.write( "Let  x  be the numerator of the fraction.
\n" ); document.write( "Then the denominator is  (x+5),  according to the first condition, and the fraction is  \"x%2F%28x%2B5%29\".\r
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\n" ); document.write( "\n" ); document.write( "According to the second condition,  you have an equation \r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B6%29%2F%28%28x%2B5%29%2B4%29\" = \"2%2A%28x%2F%28x%2B5%29%29\".\r
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\n" ); document.write( "\n" ); document.write( "Simplify and solve it:\r
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\n" ); document.write( "\n" ); document.write( "(x+6)*(x+5) = 2x*(x+9),\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+6x+%2B+5x+%2B+30\" = \"2x%5E2+%2B+18x\",\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B+7x+-+30\" = \"0\"\r
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\n" ); document.write( "\n" ); document.write( "This equation has the roots  x = 3  and  x = -10.\r
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\n" ); document.write( "\n" ); document.write( "Thus the fractions are  \"3%2F%283%2B5%29\" = \"3%2F8\"  and  \"%28-10%29%2F%28-10%2B5%29\" = \"-2\" = \"%28-2%29%2F1\".\r
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\n" ); document.write( "\n" ); document.write( "The second number does not satisfies the problem condition, while the first does.\r
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\n" ); document.write( "\n" ); document.write( "But be careful !!!\r
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\n" ); document.write( "\n" ); document.write( "The fraction  \"3%2F8\"  satisfies the condition.\r
\n" ); document.write( "\n" ); document.write( "The fraction  \"6%2F16\"  is the same number,  but do not satisfies the condition.  So, this problem is,  actually,  a danger play with words. \r
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