document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=992040>Question 992040</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve a 3x3 system of equations when the variables don't cancel out? For example, let's say your equations are 5x+7y=2 and 2x+9y=3. Can you multiply the first equation by 9 and the second equation by -7? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #611734 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52780)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=611734\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
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document.write( "If you want to exclude x, you may multiply the first equation by 2 (both sides) and the second equation by (-5) and then add them.\r<BR>\n" );
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document.write( "If you want to exclude y, you may multiply the first equation by 9 (both sides) and the second equation by (-7) and then add them.\r<BR>\n" );
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