document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=992113>Question 992113</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if 10 is subtracted from one-half of a number, the result is 2 more than one-third of the number. What is the number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #611733 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=611733\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/2x-10= 1/3x+2 multiply both denominators: 2*3= 6. Now multiply both sides times 6:\r<BR>\n" );
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document.write( "(6)1/2x-(6)10= (6)1/3x+(6)2<BR>\n" );
document.write( "3x-60= 2x+12 Now do this on BOTH sides: Subtract 2x; add 60. Do it and you'll have:<BR>\n" );
document.write( "x= 72 Let's put this number in the original equation and see if we've got the correct answer:\r<BR>\n" );
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document.write( "1/2(72)-10= 1/3(72)+2<BR>\n" );
document.write( "36-10= 24+2<BR>\n" );
document.write( "26= 26 We have the correct answer, x= 72 </SPAN>\n" );
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