document.write( "Question 992003: Roy leaves for work at 7 am travelling at 40 kph. His sister Susan finds out that he has forgotten his briefcase, she leaves at 7:05 am chasing him at 50 kph. At what time Susan will catch up with Roy? \n" ); document.write( "

Algebra.Com's Answer #611675 by josgarithmetic(39618) $\"\"$ $\"About$

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Time interval from 7:05 AM and 7:00 AM is 5 minutes which is $\"1%2F12\"$ of an hour. RT=D relates rate, time, distance for uniform travel rates.\r
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document.write( "Variable assignments are implied in this table.\r\n" );
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document.write( "         speed       time       distance\r\n" );
document.write( "ROY        40        t+1/12      d\r\n" );
document.write( "SUE        50         t          d\r\n" );
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