document.write( "Question 991916: Please help me solve this: \r
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document.write( "A man is four times as old as his son. In five years' time he will be three times as old as his son. Find their present ages. \n" );
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Algebra.Com's Answer #611666 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "S=son's age; F=father's age=4S \n" ); document.write( ". \n" ); document.write( "F+5=3(S+5) . Substitute for F. \n" ); document.write( "4S+5=3S+15 \n" ); document.write( "S=10 \n" ); document.write( "ANSWER 1: The son is 10 years old. \n" ); document.write( ". \n" ); document.write( "F=4S=4(10)=40 \n" ); document.write( "ANSWER 2: The father is 40 years old. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "F+5=3(S+5) \n" ); document.write( "40+5=3(10+5) \n" ); document.write( "45=3(15) \n" ); document.write( "45=45\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |