document.write( "Question 991991: Carlos's average speed for driving a 4-hour trip was 50mph. During the first two hours, he drove 60mph. What was his average driving speed for the last 2 hours? \n" ); document.write( "
Algebra.Com's Answer #611656 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "To average 50mph for 4 hours he drove: \n" ); document.write( ". \n" ); document.write( "(50mph)(4hrs)=200 miles \n" ); document.write( ". \n" ); document.write( "During 2 hours at 60mph: \n" ); document.write( "(60mph)((2hrs)=120 miles \n" ); document.write( ". \n" ); document.write( "During the last 2 hours he drove: \n" ); document.write( "200 mi-120 mi=80 mi \n" ); document.write( ". \n" ); document.write( "His average speed was: \n" ); document.write( "80mi/2hr=40mi/hr \n" ); document.write( ". \n" ); document.write( "ANSWER: His average speed the last 2 hours was 40 miles per hour. \n" ); document.write( " |