document.write( "Question 991918: I need help with this: Find the value of k for which \"y+=+1%2Fk\" sin k x has a period of \"4pi\" \n" ); document.write( "
Algebra.Com's Answer #611637 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
i believe your answer is that k = 1/2.\r
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\n" ); document.write( "\n" ); document.write( "here's why.\r
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\n" ); document.write( "\n" ); document.write( "the equation is y = 1/k * sin(kx)\r
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\n" ); document.write( "\n" ); document.write( "k is the frequency.\r
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\n" ); document.write( "\n" ); document.write( "the period is equal to 2pi / frequency.\r
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\n" ); document.write( "\n" ); document.write( "the period is 4pi.\r
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\n" ); document.write( "\n" ); document.write( "you get 4pi = 2pi / k\r
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\n" ); document.write( "\n" ); document.write( "solve for k to get k = 2pi / 4pi which is equal to 1/2.\r
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\n" ); document.write( "\n" ); document.write( "a wrinkle in this problem is that k is also involved in the amplitude.\r
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\n" ); document.write( "\n" ); document.write( "disregard that for purposes of solving the problem since the frequency and the period are you main interests.\r
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\n" ); document.write( "\n" ); document.write( "your equation becomes y = 1/(1/2) * sin (1/2 * x).\r
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\n" ); document.write( "\n" ); document.write( "the graph of that equation is shown below:\r
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\n" ); document.write( "\n" ); document.write( "note that the amplitude is 2.\r
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\n" ); document.write( "\n" ); document.write( "normally it is 1, but 1/(1/2) is equal to 2.\r
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\n" ); document.write( "\n" ); document.write( "the k affected the amplitude as well as the period.\r
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