document.write( "Question 991904: The sum of 3 numbers is 91. The second number is twice as big as the first. The third number is twice as big as the second. What are the values? \n" ); document.write( "
Algebra.Com's Answer #611617 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "F=first number; S=second number=2F; T=third number=2S=4F \n" ); document.write( ". \n" ); document.write( "F+S+T=91 \n" ); document.write( "F+2F+4F=91 \n" ); document.write( "7F=91 \n" ); document.write( "F=13 \n" ); document.write( "S=2F=2(13)=26 \n" ); document.write( "T=4F=4(13)=52 \n" ); document.write( ". \n" ); document.write( "ANSWER: The three numbers are 13, 26, and 52 \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "F+S+T=91 \n" ); document.write( "13+26+52=91 \n" ); document.write( "91=91 \n" ); document.write( " |