document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=991843>Question 991843</A>: <I><SPAN STYLE=\"word-break: break-all;\"> maria and tim sold candy  bars for a fundraiser.maria sold 7 less than twice the number of candy bars that tim sold. in total ,maria and tim sold 137 candy bars.find the amount of candy bars sold by each. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #611577 by </B><A HREF=/tutors/aboutme.mpl?userid=18leunggn2><B>18leunggn2(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=18leunggn2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=611577\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Maria's candy bars can be substituted by x<BR>\n" );
document.write( "Therefore, Tim's total number of candies is 2x-7 (twice the amount of x, 7 less)<BR>\n" );
document.write( "137 is the total number of candies sold by both, so x+2x-7 is 137.<BR>\n" );
document.write( "By gathering like terms, 3x-7 must equal 137<BR>\n" );
document.write( "Then, add 7 to both sides, so 3x is 144<BR>\n" );
document.write( "To find x, divide both sides by 3<BR>\n" );
document.write( "x=48\r<BR>\n" );
document.write( "\n" );
document.write( "So, Maria sells 48 candies<BR>\n" );
document.write( "Tim sells 2*48-7 candies, which is 89 candies </SPAN>\n" );
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