document.write( "Question 991845: A positive number is divided into two parts such that the squares of the two parts is 20. The square of the larger number is 8 times the smaller number. Take the smaller number as x.
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Algebra.Com's Answer #611576 by Theo(13342)\"\" \"About 
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x is the smaller number.
\n" ); document.write( "y is the larger number.
\n" ); document.write( "x^2 + y^2 = 20
\n" ); document.write( "you are given that the square of the larger number is equal to 8 time the smaller number.
\n" ); document.write( "that gets you y^2 = 8x.
\n" ); document.write( "rpelace y^2 with 8x in the original equation to get:
\n" ); document.write( "x^2 + 8x = 20
\n" ); document.write( "subtract 20 from both sides of the equation to get:
\n" ); document.write( "x^2 + 8x - 20 = 0
\n" ); document.write( "factor this quadratic equation to get:
\n" ); document.write( "(x+10) * (x-2) = 0
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = -10 and x = 2
\n" ); document.write( "since x has to be positive, you get x = 2 as your potential solution.
\n" ); document.write( "when x = 2, y^2 = 8x = 16.
\n" ); document.write( "this makes y = 4
\n" ); document.write( "your solution is that x = 2 and y = 4
\n" ); document.write( "x^2 + y^2 = 20 becomes 2^2 + 4^2 = 20 which becomes 4 + 16 = 20 which becomes 20 = 20.
\n" ); document.write( "this confirms the values are good.
\n" ); document.write( "you get:
\n" ); document.write( "x = 2 and y = 4 as your solution.
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