document.write( "Question 991692: Julie is z years old, her father is 4 times as old as Julie, while her mother is 7 years younger than her father.
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document.write( "A) Write an expression for Julies fathers age.
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document.write( "B) Write an expression for Julies mothers age.
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document.write( "C) Their 3 ages add up to 101. Write an expression for their total ages and find Julie's age. \n" );
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Algebra.Com's Answer #611516 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Julie is z years old, her father is 4 times as old as Julie, while her mother is 7 years younger than her father. \n" ); document.write( "A) Write an expression for Julies fathers age. \n" ); document.write( "f = 4z \n" ); document.write( "B) Write an expression for Julies mothers age. \n" ); document.write( "m = f - 7 \n" ); document.write( "C) Their 3 ages add up to 101 \n" ); document.write( " Write an expression for their total ages \n" ); document.write( "z + f + m = 101 \n" ); document.write( ": \n" ); document.write( "find Julie's age. \n" ); document.write( "Rewrite the 1st equation \n" ); document.write( "4z = f \n" ); document.write( "z = \n" ); document.write( "or \n" ); document.write( "z = .25f \n" ); document.write( ": \n" ); document.write( "In the total age equation, replace z and m \n" ); document.write( ".25f + f + (f-7) = 101 \n" ); document.write( "2.25f = 101 + 7 \n" ); document.write( "2.25f = 108 \n" ); document.write( "f = 108/2.25 \n" ); document.write( "f = 48 yrs is fathers age \n" ); document.write( "\"find Julie's age. \" \n" ); document.write( "z = .25(48) \n" ); document.write( "z = 12 yrs is Julie's age \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this out, find mom's age: 48 - 7 = 41 \n" ); document.write( "Total ages \n" ); document.write( "12 + 48 + 41 = 101\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |