document.write( "Question 991671: Lizzys brother is 4 times older than her. Six years later, her brother was only twice as old as she was then. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #611511 by ankor@dixie-net.com(22740)\"\" \"About 
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let b = brother's age
\n" ); document.write( "let z = Liz's age
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\n" ); document.write( "write an equation for each statment
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\n" ); document.write( " Lizzy's brother is 4 times older than her.
\n" ); document.write( "b = 4z
\n" ); document.write( " Six years later, her brother was only twice as old as she was then.
\n" ); document.write( "b + 6 = 2(z + 6)
\n" ); document.write( "b + 6 = 2z + 12
\n" ); document.write( "b = 2z + 12 - 6
\n" ); document.write( "b = 2z + 6
\n" ); document.write( "replace b with 4z
\n" ); document.write( "4z = 2z + 6
\n" ); document.write( "4z - 2z = 6
\n" ); document.write( "2z = 6
\n" ); document.write( " z =6/2
\n" ); document.write( "z = 3 yrs is Liz's age
\n" ); document.write( "then
\n" ); document.write( "4(3) = 12 yrs is brother's age
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\n" ); document.write( "you can confirm this by using these ages in the 2nd statement
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