document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=991428>Question 991428</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the manager at a restaurant found that the cost to produce 150 cups of coffee is $21, while the cost to produce 300 cups of coffee is $36. assume the relationship between the cost y to produce x cups of coffee is linear.\r<BR>\n" );
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document.write( "a.) write a linear equation that expresses the cost,y, in terms of the number of cups of coffee,x.<BR>\n" );
document.write( "b.) how many cups of coffee are produced if the cost of production is $56? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #611481 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=611481\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The total cost (y) is the sum of fixed cost (F)<BR>\n" );
document.write( "and the cost per cup (C) times the number of cups (x):<BR>\n" );
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document.write( "y=F+Cx<BR>\n" );
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document.write( "First, find C:<BR>\n" );
document.write( "y=F+Cx<BR>\n" );
document.write( "$21=F+C(150)<BR>\n" );
document.write( "F=$21-C(150) Use as F<BR>\n" );
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document.write( "$36=F+C(300)<BR>\n" );
document.write( "F=$36-C(300)  . Replace F from above.<BR>\n" );
document.write( "$21-C(150)=$36-C(300) . Add C(300) to each side.<BR>\n" );
document.write( "$21+C(150)=$36 . Subtract $21 from each side.<BR>\n" );
document.write( "C(150)=$15<BR>\n" );
document.write( "C=$0.10 . Each cup costs $0.10 to produce.<BR>\n" );
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document.write( "Next, find fixed cost (F):<BR>\n" );
document.write( "F=$21-C(150)<BR>\n" );
document.write( "F=$21-$0.10(150)<BR>\n" );
document.write( "F=$21-$15<BR>\n" );
document.write( "F=$6 . The fixed cost is $6.<BR>\n" );
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document.write( "(a). The equation:<BR>\n" );
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document.write( "y=F+Cx.<BR>\n" );
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document.write( "y=$6+$0.10x<BR>\n" );
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document.write( "(b). For cost y=$56<BR>\n" );
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document.write( "y=$6+$0.10x<BR>\n" );
document.write( "$56=$6+$0.10x<BR>\n" );
document.write( "$50=$0.10x<BR>\n" );
document.write( "500=x . ANSWER: 500 cups are produced for $56. </SPAN>\n" );
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