document.write( "Question 991261: At a certain vineyard it is found that each grape vine produces about 10 pounds of grapes in a season when about 600 vines are planted per acre. For each additional vine that is planted, the production of each vine decreases by about 1 percent. So the number of pounds of grapes produced per acre is modeled by
\n" ); document.write( "A(n) = (600 + n)(10 − 0.01n)\r
\n" ); document.write( "\n" ); document.write( "where n is the number of additional vines planted. Find the number of vines that should be planted to maximize grape production. \n" ); document.write( "
Algebra.Com's Answer #611347 by ankor@dixie-net.com(22740)\"\" \"About 
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At a certain vineyard it is found that each grape vine produces about 10 pounds of grapes in a season when about 600 vines are planted per acre. For each additional vine that is planted, the production of each vine decreases by about 1 percent. So the number of pounds of grapes produced per acre is modeled by
\n" ); document.write( "A(n) = (600 + n)(10 − 0.01n)
\n" ); document.write( "where n is the number of additional vines planted.
\n" ); document.write( " Find the number of vines that should be planted to maximize grape production.
\n" ); document.write( ":
\n" ); document.write( "A(n) = (600 + n)(10 − 0.01n)
\n" ); document.write( "FOIL
\n" ); document.write( "A(n) = 6000 - 6n + 10n - .01n^2
\n" ); document.write( "A quadratic equation
\n" ); document.write( "y = -.01n^2 + 4n + 6000
\n" ); document.write( "The axis of symmetry will give us the maximum x = -b/(2a)
\n" ); document.write( "In this equation x = n; b = 4;
\n" ); document.write( "n = \"%28-4%29%2F%282%2A-.01%29\"
\n" ); document.write( "n = 200 more vines, a total of 800 vines for max grape production
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