document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=991460>Question 991460</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if an angle is 57 degrees more than twice its complement find measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #611335 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=611335\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  if an angle is 57 degrees more than twice <BR>\n" );
document.write( "its complement find measure of each angle.<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Angle :: x<BR>\n" );
document.write( "complement:: 90-x<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "x = 2(90-x)+57<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x = 180-2x+57<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "3x = 237<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Ans: x = 79<BR>\n" );
document.write( "90-x = 11<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );